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Class 12 Chemistry Chemical Kinetics Notes and Important Questions

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Notes for Class 12 Chemical Kinetics (Chemistry) are shown above.

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Important Questions

1
LongModel Question · Set BNo solution yet

A hypothetical reaction, 3X + 2Y ⟶ Z

Expt

[X] (mol L⁻¹)

[Y] (mol L⁻¹)

The Rate of formation of Z (mol L⁻¹ min⁻¹)

1

0.1

0.1

1 × 10⁻³

2

0.1

0.4

4 × 10⁻³

3

0.2

0.4

8 × 10⁻³

4

0.5

A

1.8 × 10⁻²

a.
Short2+1+2

a) Determine the value of rate constant.
b) Calculate the value of A.
c) Write rate law equation.

b.
Short2m

What is pseudo first order reaction? Write one suitable example.

c.
Short1m

Draw the diagram showing effective collision.

2
ShortModel QuestionNo solution yet
a.
Short2m

Write down the differences between rate of reaction and rate constant.

b.
ShortNo solution yet

For the reaction $2A + B \rightarrow \text{product}$, following data were obtained:

null

i.
Short1m

order with respect to $A$ and $B$. $(1)$

ii.
Short1m

the value of the rate constant of the reaction

iii.
Short1m

the rate of reaction when the concentration of $A$ and $B$ is $0.5\ \text{M}$ and $0.4\ \text{M}$, respectively.

Or
b.
ShortNo solution yet

Four metals $A$, $B$, $C$ and $D$ react in the following way:

$B$ displaces only $A$ from solution. Only $D$ and $C$ displace hydrogen from $1\ \text{M HCl}$ solution. None of the metals will displace C from solution. Answer the followings:

i.
Short1m

Make the activity series of four metals with hydrogen

ii.
ShortNo solution yet

The standard potential for the following electrodes are:

null

i.
Short2m

Construct the galvanic cell by pointing out cathode and anode.

ii.
Short1m

With $1\ \text{M}$ solution of the ions, what will be EMF of cell?

iii.
Short

Will the reaction occur:

null

Occur? Give reasons. $(1)$

3
Short5mOld Question · 2082

Define instantaneous rate of reaction. Write down the rate expressions of the following reaction.

2N₂O₅(g) → 4NO₂(g) + O₂(g)

If 2.24 litres of O₂ at NTP is produced in 30 minutes, what is the rate of disappearance of N₂O₅(g)?

4
MCQ1mOld Question · 2082

The half-life of a certain reaction is 50 seconds, and it remains constant even if the initial concentration of the reaction is doubled. What is the order of the reaction?

A

Zero-order reaction

B

First-order reaction

C

Second-order reaction

D

Pseudo-first order reaction

1
ShortModel Question · Set ANo solution yet

For a gaseous reaction:
2A + B ⟶ C. The reaction is first order with respect to A and zero order with respect to B.

a.
Short1m

Define order of reaction.

b.
Short1m

Write the rate law for above reaction.

c.
Short2m

How many times the rate of reaction increase if the concentration of both A and B are doubled?

d.
Short1m

If the temperature increases by 20°C what will be its effect in rate of reaction?

2
MCQ1mModel Question · Set B

Half life period is directly proportional to the initial concentration of the reactant. What is the order of the reaction?

A

zero order

B

second order

C

first order

D

third order

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Past Question Analysis

Historical exam-pattern data from past NEB question papers — not a prediction of future questions.

2

Question Items

6

Total Marks

1

Papers Appeared In

YearQuestion ItemsMarks
208226

Also appears in 4 model questions (not counted above — model sets aren't actual NEB exam history).

Chemical Kinetics explores the rate at which chemical reactions occur and the factors affecting reaction rates. Students study rate laws, rate constants, order and molecularity, integrated rate equations, half-life, collision theory, activation energy, Arrhenius equation and catalysis.

This page covers Chemical Kinetics, chapter 3 of 22 in the Class 12 Chemistry syllabus set by the National Examination Board (NEB). 10 important questions for this chapter are available, each with a full solution.

For numerical and derivation-based chapters like this one, working through past NEB questions is usually more useful than re-reading notes alone — try solving each important question above before checking the solution, then compare your working step by step.